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High School/JEE/NEET/IPhO Physics | 17-19 Yrs

Simple Harmonic Motion
Duration: 13.12 Min
 
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Duration: 6.04 Min
 
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Duration: 4.48 Min
 
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Duration: 8.14 Min
 
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Duration: 2.12 Min
 
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Duration: 1.40 Min
 
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Duration: 2.14 Min
 
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Duration: 2.13 Min
 
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Duration: 11.22 Min
 
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Duration: 4.37 Min
 
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Duration: 10.57 Min
 
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Duration: 7.21 Min
 
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Duration: 3.02 Min
 
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Duration: 8.10 Min
 
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Duration: 11.30 Min
 
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Duration: 5.04 Min
 
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Module - 21 Solved Example-5
Duration: 3.30 Min
 
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Module - 22 Solved Example-6
Duration: 2.55 Min
 
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Module - 23 Solved Example-7
Duration: 1.45 Min
 
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Module - 24 Solved Example-8
Duration: 3.04 Min
 
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Module - 25 Solved Example-9
Duration: 3.00 Min
 
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Duration: 7.20 Min
 
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Duration: 8.36 Min
 
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Duration: 8.56 Min
 
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Duration: 3.34 Min
 
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Duration: 5.01 Min
 
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  1.  
  2. Sir I did not understand how did you write A and B as Rcos(phi) and Rsin(phi)?
    4 years ago by M.V.S.S KARTHIK

    Post your answer here

  3.  
  4. Sir I did not understand how did you write the values of A and B as Rcos(phi) and Rsin(phi)?
    4 years ago by M.V.S.S KARTHIK

    Post your answer here

  5.  
  6. thanks for your efforts.this is the true nationalism.
    5 years ago by ABHISHEK MISHRA

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  7.  
  8. sir, is it correct to judge the amplitude directly since max value of y=Asin(x) Bcos(x) will be root of (A^2 B^2)?
    7 years ago by Ashwin Murali
    Ans 1 ->
    sorry,root of (A^2 B^2)
    7 years ago by Ashwin Murali

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  9.  
  10. sir can we substitute any other constants for A and B?
    8 years ago by saikiran

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  11.  
  12. Sir but why have you exactly substituded A and B as function of theta
    9 years ago by Mohak Sharma
    Ans 1 ->
    Here R and phi/theta are both constants and A and B are also constants so I have just defined a relation among constants with which we are able to transform the given equation in the known form of equation of SHM... thats it...
    9 years ago by Physics Galaxy

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  13.  
  14. how can you say that both A and B are function of theta
    10 years ago by manish reddy yedulla
    Ans 1 ->
    please reply
    10 years ago by manish
    Ans 2 ->
    A and B are constants and any two constants can always be expressed in terms of two other constants... which we have done here to reduce the given function in the form of SHM...
    9 years ago by Physics Galaxy
    Ans 3 ->
    Test Content
    7 years ago by Anushree Wasule

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